No — array indexes start at zero, and go up to length-1.
Here is a program that asks the user for an integer and for
an array index where it is to be placed.
Only indexes 0 through 9 are allowed.
Any other index  causes an 
IndexOutOfBoundsException.
import java.util.* ;
public class IndexPractice
{
  public static void main ( String[] a )
  {
    Scanner scan = new Scanner( System.in );
    int data=0, slot=0 ;
    int[] value = new int[10];
    try
    { 
      System.out.print("Enter the data: ");
      data = scan.nextInt();
      System.out.print("Enter the array index: ");
      slot = scan.nextInt();
      value[slot] = data;
    }
    catch (InputMismatchException ex )
    {  
      System.out.println("This is your problem: " +  ex.getMessage()   
          + "\nHere is where it happened:\n");
       ex.printStackTrace();  
    } 
    catch (IndexOutOfBoundsException ex )
    {  
       System.out.println("This is your problem: " +  ex.getMessage()   
          + "\nHere is where it happened:\n");
       ex.printStackTrace(); 
     } 
    System.out.println("Good-by" );
  }
}
If the user enters:
Enter the data: 8 Enter the array index: 10will an exception be thrown?